Question

Find the equation of the tangent line for the given function at x =(1/6) pi

f(x)= 4sec(x)

Answer 1

f'(x)= 4sec(x)tan(x)
then...

Answer 2

now plug in pi/6 this will give you the slope of the line and a point (pi/6,f(pi/6)), use this information and the form y = mx+b

Answer 3

I dont understand what happens at sec(pi/6) or tan(pi/6)

Answer 4

sec(pi/6) = 1/cos(pi/6) = 1/(sqrt(3)/2) = 2/sqrt(3)

Answer 5

so the slope is 2?