Question

Christopher is 68 years old and Gabriela is 4 years old.How many years will it take until Christopher is only 5 times as old as Gabriela? (yes i know I have to set up an equation. but thats the tricky part)

Answer 1

5(4+x).... that could be part of it :) do you see why?

Answer 2

yeah but what about the other side of the equation?

Answer 3

because i also have to include the 68 in there

Answer 4

You can solve this question in two ways
1) Setting up an equation

Christopher's age=68, let X no.of years pass before Christopher becomes 5 times as old as Gabriela..so Christopher's age after X years=68+X. Gabriela's age after X years=4+X.
Now according to the criterion set, 68+X=5*(4+X)
now solve for X.answer should be 12

2)Without setting up the equation

Difference between Christopher's and Gabriela's Age=68-4=64 years
Now. Christopher will at one point be only 5 time as old as Gabriela. At that point, Difference in ages= 5Gabriela-Gabriela=4Gabriela
--> 4Gabriela=64 or Gabriela=16 years
which means 16-4=12 more years need to pass

Answer 5

okay thank you so much :]