Question

find the equation whose roots are each two more than the roots of x^3 - 4x^2 + 3x - 2 = 0 ?

Answer 1

let roots be a,b,c
now
a+b+c=4
ab + bc + ca = 3
abc = 2

the new eqn has roots, a+2,b+2,c+2..

make those substitutions

let the new eqn be
x^3 + px^2 + qx + r =0

you know, (a+2) + (b+2) + (c+2) = -p
(a+2)(b+2) + (b+2)(c+2) + (c+2)(a+2)= q
(a+2)(b+2)(c+2) = -r

make those comparisons..

Answer 2

why does a+b+c equal 4?

Answer 3

sum of roots = -b/a ..rightt ?