Question

sinA, cosA, tanA are in GP, the the value of
cot^6(A) - cot^2(A)

Answer 1

i am getting 1

Answer 2

did u reach to the point
1/cos^3 A - 1/ cos A ??

Answer 3

how much of it did u solve ? and is the answer = 1 ?

Answer 4

yep

Answer 5

can u say d whole procedure

Answer 6

i can, but i need to know how much did u solve, then i'll continue from there

Answer 7

did u get sin^2 A = cos ^3 A ?

Answer 8

no

Answer 9

u know the meaning of GP ?

Answer 10

yeah... of course

Answer 11

so sin A tan A = cos^2 A
can u get
sin^2 A = cos ^3 A
from here ?

Answer 12

ya... i got

Answer 13

now write cot A in terms of cosA and sin A

Answer 14

cos A/ sin A = cot A

Answer 15

COT^2 A = COS A

Answer 16

i mean write it here :cot^6(A) - cot^2(A)
cos^6 A/ sin^6 A - cot^2 A / sin^2 A

Answer 17

cos^6 A/ sin^6 A - cos^2 A / sin^2 A

Answer 18

i did do it

Answer 19

so sin^6 A = cos^9 A
right ?