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OpenStudy (anonymous):
Nakim simplified \[3\sqrt{2X} + X \sqrt{8X} - 5 \sqrt{18} and got -10X \sqrt{2X} \] for an answer
OpenStudy (anonymous):
Part 1: Using complete sentences, explain what Nakim did wrong.
Part 2: Show all your work to simplify the expression.
jhonyy9 (jhonyy9):
what is your opinion from this ?
can you solve it right here ?
OpenStudy (anonymous):
no lol i need help :(
jhonyy9 (jhonyy9):
so because the first term is 3sqrt(2x) you need simplifie every terms in the same station
- so than you need to simplifie xsqrt(8x) = ? so and from -5sqrt(18) a term simplified on what you can do it
ok ?
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jhonyy9 (jhonyy9):
so sqrt(8x) =
what is 8 using exponent,power of 2 ?
OpenStudy (anonymous):
4?
jhonyy9 (jhonyy9):
this sign that 2 on exponent 4 equal 8
not is right
OpenStudy (anonymous):
huh?
jhonyy9 (jhonyy9):
so if 8=2*2*2 than result that 2 on exponent ??? equal 8
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OpenStudy (anonymous):
3 :D
jhonyy9 (jhonyy9):
yes - so this is very easy
yes ?
OpenStudy (anonymous):
wait can u explain step by step how to SOLVE THIS !!!!
Whats the first step and use the equation tab lol
jhonyy9 (jhonyy9):
than xsqrt(8x) = ?
jhonyy9 (jhonyy9):
yes i wann to make you solving this step by step here now
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OpenStudy (anonymous):
okay so we need simply everything
jhonyy9 (jhonyy9):
yes than just you need answering my questions please
ok ?
OpenStudy (anonymous):
\[3\sqrt{2X}\] okay can we simplify that?
jhonyy9 (jhonyy9):
but first there is xsqrt8x =
OpenStudy (anonymous):
we do that one next
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jhonyy9 (jhonyy9):
yes because 3sqrt2x not can simplifie again
OpenStudy (anonymous):
oh so that one is simplified okay so now we do \[X \sqrt{8X}\]
jhonyy9 (jhonyy9):
ys how can you simplifie it using this sqrt8 = sqrt(2*2*2) =
OpenStudy (anonymous):
\[\sqrt{2 * 2 * 2 }\]
jhonyy9 (jhonyy9):
yes how you simplifie it ?
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OpenStudy (anonymous):
hmmm idk show me please?
jhonyy9 (jhonyy9):
ok
sqrt(2*2*2) = sqrt(2^2 *2) = sqrt2^2 *sqrt2
so than sqrt2^2 =
jhonyy9 (jhonyy9):
???
OpenStudy (anonymous):
hmmm not surel ol
jhonyy9 (jhonyy9):
why how many is sqrt(x^2) = ???
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OpenStudy (anonymous):
2*2
jhonyy9 (jhonyy9):
what is 2*2 ?
OpenStudy (anonymous):
idk im confused? LOL
jhonyy9 (jhonyy9):
so if do you know that sqrt(x^2) =x so than sqrt(2^2) = ?
OpenStudy (anonymous):
X :D
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OpenStudy (anonymous):
right?
jhonyy9 (jhonyy9):
not is so if sqrt(x^2) = x so than sqrt(2^2) =2
ok ?
OpenStudy (anonymous):
okay
jhonyy9 (jhonyy9):
so than sqrt(2^3) = ?
OpenStudy (anonymous):
3?
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jhonyy9 (jhonyy9):
when you know that sqrt(2^2)=2
and sqrt(2^3) =sqrt(2^2 *2) so than how you have got 3 ?
jhonyy9 (jhonyy9):
sqrt(2^3) = sqrt(2^2 *2)=sqrt(2^2) *sqrt2 =
jhonyy9 (jhonyy9):
there is all what you need to know
check it please
OpenStudy (anonymous):
so what does it look like simplified?
jhonyy9 (jhonyy9):
so if sqrt2^2 =2 than result that sqrt(2^2 *2) = 2sqrt2
yes ?
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jhonyy9 (jhonyy9):
so than xsqrt8x = ?
OpenStudy (anonymous):
So it looks like this right
\[X \sqrt{8X} = 2\sqrt{2}\]
jhonyy9 (jhonyy9):
so and where is x ?
OpenStudy (anonymous):
hmmm on top of the 2 on the inside right?
jhonyy9 (jhonyy9):
write it please !
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OpenStudy (anonymous):
\[X \sqrt{8X} = 2\sqrt{2^{^{2}}}\]
OpenStudy (anonymous):
i meant to put X lol
jhonyy9 (jhonyy9):
how ?
OpenStudy (anonymous):
whats the answer?
OpenStudy (anonymous):
what would it look like?
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jhonyy9 (jhonyy9):
xsqrt8x = ?
OpenStudy (anonymous):
idk
jhonyy9 (jhonyy9):
xsqrt8x = xsqrtx * sqrt8 = ?
OpenStudy (anonymous):
?
jhonyy9 (jhonyy9):
do you know that sqrt8 = ?
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OpenStudy (anonymous):
no
jhonyy9 (jhonyy9):
before you have solved it
OpenStudy (anonymous):
im confuised
jhonyy9 (jhonyy9):
look it little up
OpenStudy (anonymous):
k
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OpenStudy (anonymous):
just tell me
jhonyy9 (jhonyy9):
you need to learn it how you can solve it ,right ?
OpenStudy (anonymous):
just tell me this part so we can move on
jhonyy9 (jhonyy9):
ok look so if sqrt8 = 2sqrt2 so than xsqrt8x = 2xsqrt(2x)
do you know how i have got it ?
OpenStudy (anonymous):
okay so thats the simplyfy right?
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jhonyy9 (jhonyy9):
yes but you need to continue
how is your exercise again ?
OpenStudy (anonymous):
so the answer is \[X \sqrt{8X} = 2X \sqrt{2X}\]
jhonyy9 (jhonyy9):
for this midle term yes
OpenStudy (anonymous):
okay lol and the last one to simply is
\[-5\sqrt{18X}\]
jhonyy9 (jhonyy9):
but in your exercise you not have wrote it hence ,check it please
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jhonyy9 (jhonyy9):
there is -5sqrt18 right ?
OpenStudy (anonymous):
yes
jhonyy9 (jhonyy9):
so than how is correct ?
OpenStudy (anonymous):
what do u mean? thats the next part lol we have to do
jhonyy9 (jhonyy9):
so check it please your exercise how you have wrote firstly and how you have wrote it here little up
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jhonyy9 (jhonyy9):
inside radical need being x or not ?
OpenStudy (anonymous):
oh i forgot to put x at the beggind its suppose to be x
jhonyy9 (jhonyy9):
so than correct is -5sqrt18x
yes ,
jhonyy9 (jhonyy9):
so than how you can simplifie it ?
OpenStudy (anonymous):
hmmm im not sure
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jhonyy9 (jhonyy9):
why if do you know that 18=2*9=2*3^2
so than how will be simplified ?
OpenStudy (anonymous):
2sqrt9
jhonyy9 (jhonyy9):
why ?
when sqrt9 = sqrt3^2 =3
OpenStudy (anonymous):
hmm true so 7sqrt2
jhonyy9 (jhonyy9):
how you have got 7 ?
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OpenStudy (anonymous):
im not sure lol
jhonyy9 (jhonyy9):
so there is -5sqrt18x =
jhonyy9 (jhonyy9):
when sqrt18=sqrt(3^2 *2) =3sqrt2
OpenStudy (anonymous):
hmm okay
jhonyy9 (jhonyy9):
so than -5sqrt18x = ?
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