find the equation of the tangent at x=2 at the following function:
f(x)= (4x^3)/(1-4x)^5

Question

find the equation of the tangent at x=2 at the following function:
f(x)= (4x^3)/(1-4x)^5

hartnn · Answer

can u differentiate f(x) ?

anonymous · Answer

yeah wait

anonymous · Answer

4x^2(8x+3)/(1-4x)^6

hartnn · Answer

u using quotient rule, right ? 
plz, verify it again, thats not right...

anonymous · Answer

i used wolfram alpha  you can use it, but i cant find the equation :/

hartnn · Answer

hartnn · Answer

now put x= 2 int that equation, 
you will get the slope of line

hartnn · Answer

put x= 2 in f(x) also 
so u get a point on that curve(x,y)
then the equation of line is :
(y-y1)=m(x-x1)

hartnn · Answer

point(x1,y1)*

anonymous · Answer

okay ill try that too but ive been putting x=2 in the equation you sent but im not getting the answer thanks anyways!