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Solve 3x+2y=7 3x^2-2y^2=25
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ANSWER = {(3,-1),(11,-13)}
find x from 3x+2y=7 put it in 2nd equation
ok wait
\[x=\frac{ 7-2y }{ 3 } RIGHT?\]
49-28y+4y^2/3 -2y^2=25
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am i doing right
yes. (49-28y+4y^2)/3 -2y^2=25 first multiply 3 to eliminate denominator
25x3=75
and -2y^2 *3 = -6y^2
2y^2-28y-26=0
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how u get +2y^2?? i get -2y^2
4y^2-2y^2
4y^2-6y^2
why are u multiplying 3 by -2y^2 we are cross multiplying and it will be 25x3=75
i am multiplying 3 throught , to each term
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\[\frac{ 49-28y+4y^2 }{ 3 }-2y^2=25\]
ok
\[2y^2+28y+26=0\]
yes.
y=-4 and y=13
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sorry -13
i m getting -1,-13
sorry i am getting -1 and -13
i have got the answers thank u all
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