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Identify the vertex for the graph of y = −2x^2 + 8x − 1.
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the vertex of the graph y = ax^2 + bx + c is given by x-vertex = -b/2a as you found the x-vertex you just plug it into your equation and find y-vertex in our case a= -2 b = 8 c = -1 so what is -b/2a ?
.5 ?
if b = 8 and a = -2 it means that 2a = -4 so -(b/2a) = - (8/-4) = 2
this is x-vertex.. now in order to find the y-vertex you only have to plug 2 into the equation so what is y(2) ?
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are you there ? trying ?
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It would be b because when you work it out it cannot be c.
yes.. this is the right answer (b) y(2) = -2* (2)^2 +8*2 -1 = -8 + 16 -1 = 7 so (2,7)
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Yay ! thanks
yw :)
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