Question

how is it possible ?

x=(pi +3)/2
2x=pi +3
2x(pi -3)=(pi +3)(pi -3)
2pi*x -6x =(pi)^2 -9
9 -6x =(pi)^2 -2pi*x
9 -6x +x^2 =(pi)^2 -2pi*x +x^2
(3 -x)^2 =(pi -x)^2
3-x = pi -x
pi =3

Answer 1

O.O

Answer 2

what you are doing is a=b, a^2 = b^2 => a = -b ...

Answer 3

I think there is a problem with third last line