I need help on this problem can someone please help me it is an algebra 2 investment problem. Javier invests money in two accounts. He invests twice as much in an account paying 12% as he does in an account paying 7%. If he earns $310.00 in interest in one year from both accounts combined, how much did he invest altogether?

Question

anonymous · Answer

of he invests say $x$ dollars in the 7% account then he invests $2x$ dollars in the 12% account.
you will get $.07x+.12\times 2x$ dollars, which equals 310 so ste 
$$.07x+.24x=310$$ and solve for $x$ 
maybe easier to multiply by 100 and solve 
$$7x+24x=31000$$