Question

I need help on this problem can someone please help me it is an algebra 2 investment problem. Javier invests money in two accounts. He invests twice as much in an account paying 12% as he does in an account paying 7%. If he earns $310.00 in interest in one year from both accounts combined, how much did he invest altogether?

Answer 1

of he invests say \(x\) dollars in the 7% account then he invests \(2x\) dollars in the 12% account.
you will get \(.07x+.12\times 2x\) dollars, which equals 310 so ste
\[.07x+.24x=310\] and solve for \(x\)
maybe easier to multiply by 100 and solve
\[7x+24x=31000\]