Use the elimination method to solve the system of equations.( My number three key went out lol)
8u+three v =-17
three u +v=-5
The solution is ?
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OpenStudy (anonymous):
8u+3v=-17
3u+v=-5
What could you multiply one of the equations by that would make it where when you add them together, one of the variables would be eliminated?
OpenStudy (anonymous):
multiplly the second equation by three
OpenStudy (anonymous):
negative three
OpenStudy (anonymous):
Yep. What do you get when you do that?
OpenStudy (anonymous):
-6u-three v=-15
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OpenStudy (anonymous):
You shouldve got -9u-3v=15
OpenStudy (anonymous):
8u+ three v=-17
-6u= three v=15
OpenStudy (anonymous):
oh
OpenStudy (anonymous):
yeah i see
OpenStudy (anonymous):
Yep now add the equations
8u+3v=-17
-9u-3v=15
what do you get?
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OpenStudy (anonymous):
u=2
OpenStudy (anonymous):
i subtract -9u from 8
OpenStudy (anonymous):
and -17 from 15
OpenStudy (anonymous):
Yep, so now that you know u=2
plug that in for u in one of the original equations and solve for v.
OpenStudy (anonymous):
well it says substitute
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OpenStudy (anonymous):
so 2(2)+v=-5
OpenStudy (anonymous):
3(2)+v=-5
OpenStudy (anonymous):
ok so v=-1
OpenStudy (anonymous):
Nope, v=-11
v=-5-6
v=-11
OpenStudy (anonymous):
6+5
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OpenStudy (anonymous):
not 6-5
OpenStudy (anonymous):
3(2)+v=-5
6+v=-5
subtract 6 from both sides
v=-11
OpenStudy (anonymous):
so the solution is (2,-11)
OpenStudy (anonymous):
Yep.
u=2
v=-11
OpenStudy (anonymous):
ok thanks could you help me with another problem?
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OpenStudy (anonymous):
I could try
OpenStudy (anonymous):
lol well thats all we could do
OpenStudy (anonymous):
i am typing problem
OpenStudy (anonymous):
solve by elimination method.(my number three key is out still tryna fix...)
5a+2b=-three9
-5a+b=48
the solution is?
OpenStudy (anonymous):
lol, this one already has one that cancels out, so just go ahead and add them.
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OpenStudy (anonymous):
please show me what you are saying
OpenStudy (anonymous):
ook
OpenStudy (anonymous):
b+5a=-three9
OpenStudy (anonymous):
b+5a=48
5a+2b=-three9
OpenStudy (anonymous):
ok wait
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OpenStudy (anonymous):
ok you added the two end number 48 and three9
OpenStudy (anonymous):
2b+b=three b
OpenStudy (anonymous):
Did you type the equations wrong the first time?
OpenStudy (anonymous):
no just whn i attempt i did
OpenStudy (anonymous):
First you said
5a+2b=-three9
-5a+b=48
Then you said
b+5a=48
5a+2b=-three9
so which one are we doing?
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OpenStudy (anonymous):
th first one is correct
OpenStudy (anonymous):
the first one
OpenStudy (anonymous):
so i have to divide
OpenStudy (anonymous):
29
OpenStudy (anonymous):
b=29
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OpenStudy (anonymous):
what about solving for a
OpenStudy (anonymous):
-5a+(29)=48
OpenStudy (anonymous):
i think thats correct
OpenStudy (anonymous):
ok i do not know what the hck im doing on this but how i seet thee problem up for wwhat it says that what it is but all that i tried to attempt to do i do know if im right or wrong
OpenStudy (anonymous):
i dont know if im right or wrong
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OpenStudy (anonymous):
What are your answers?
OpenStudy (anonymous):
im sorry if i confusd u
OpenStudy (anonymous):
(29, ?)
OpenStudy (anonymous):
i dont know how to do thee second step
OpenStudy (anonymous):
Lets start fresh.
The equations are:
5a+2b=-39
-5a+b=48
Add them and you get
3b=9
b=3
Now that you know b, substitute it in and solve for a.
5a+2(3)=-39
5a=-45
a=-9
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