factor -7x^2+2x^3+4x-14
factor the GCF, x^2 from first two terms
factor the GCF, 2 from last two terms
i dont understand that
-7x^2+2x^3+4x-14 factor the GCF, x^2 from first two terms : x^2(-7 + 2x) + 4x - 14 factor the GCF, 2 from last two terms : x^2(-7 + 2x) + 2(2x - 7)
oh ok
:) now do u see anything common ?
-7x^2+2x^3+4x-14 factor the GCF, x^2 from first two terms : x^2(-7 + 2x) + 4x - 14 factor the GCF, 2 from last two terms : x^2(-7 + 2x) + 2(2x - 7) x^2(2x - 7) + 2(2x - 7)
can we factor (2x-7) ?
No
why No ?
i see (2x-7) is common in both the terms hmm, we can pull it out, eh ?
ok sure
yes we can factor
good :) factor it and see what u get
is it 2x^2(2x-7)
you're almost correct ! let me show u hw to factor it :)
-7x^2+2x^3+4x-14 factor the GCF, x^2 from first two terms : x^2(-7 + 2x) + 4x - 14 factor the GCF, 2 from last two terms : x^2(-7 + 2x) + 2(2x - 7) x^2(2x - 7) + 2(2x - 7) factor (2x-7) : (2x-7)(x^2+2)
x^2 remains in the first term 2 remains in the last term, so we should write that as (x^2+2), not 2x^2
so thats our final factored form : (2x-7)(x^2+2)
oh ok thanks
np
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