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Where does the plane x-y+4z=4 intersect the xy,xz and yz planes? Also, what is the parametric equation of a line perpendicular to this plane going through(3,4,8)?
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to find the intersections of each plane let z=0, y=0, and x=0 respectively
the normal vector to the plane is given by\[\vec n=\nabla f(x,y,z)\]
But if I plug in x=0, then I'll have one equation with two variables of y and z...
yes, because the intersection is a line
Ooh I think I got it, I just had to set that into the parametrics and use the "t" value to find the other values. Thanks!
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