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A projectile is thrown upward so that its distance above the ground after t seconds is h = - 16t2 + 440t. After how many seconds does it reach its maximum height?
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few ways to solve this
are you familiar with derivatives?
with a graph correct?
Without Calculus y|dw:1349657074734:dw|ou know that this graph will look like this
oh ok
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so you know it hits its maximum height at its' vertex. you know how to find the x for the vertex by \[x=\frac{-b}{2a}\]
x so happens to be time in our case =P
ohhhh
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