Question

when 2x³+mx²+x-20 is divided by (x+1) the remainder is -35. When it is divided by (x-2) the remainder is -26. What are the values of m and n ?
I have most if this question, i just need help with the last part. Thanks

Answer 1

On the last problem

Answer 2

I just checked

Answer 3

let \[h(x)= 3x^3+mx^2+nx-20\]

Answer 4

they should be 3's instead of 5's

Answer 5

\[h(-1)= 3(-1)^3+m(-1)^2+n(-1)-20\]

Answer 6

-13 = m-n