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OpenStudy (anonymous):
Why does ln(2-6x) = ln(1-3x)
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OpenStudy (anonymous):
Well, it doesn't seem to be the case... wolfram is messing with me.
OpenStudy (anonymous):
\[In(2-6x) \] is divided by 2
OpenStudy (anonymous):
I suppose thats a way to simplify it then... Ill look into these shenanigans.
OpenStudy (anonymous):
http://www.wolframalpha.com/input/?i=integrate+1%2F%282-6x%29 According to that, the answers are different when using the step by step method.
OpenStudy (anonymous):
Wow haha that totally confused me what is the whole problem you're trying to solve?
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OpenStudy (anonymous):
integral of (-1/6) ln(2-6x)
OpenStudy (anonymous):
I'm sorry, but I'm stumped on this one
OpenStudy (anonymous):
Same here... lets call it a day. We found a system error!
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