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OpenStudy (anonymous):
HELP Prove that for the quadratic function y= f(x) = a0+a1x+a2x2, the axis of symmetry is given by x_s = -a_1/2a_2. Illustrate your answer in a graph
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OpenStudy (experimentx):
find the vertex of it ...let the vertex be (a, b), then axis of symmetry is x=a
OpenStudy (anonymous):
how to find the vertex? should we assume the number e.g y= x^2+6x+8 to find the vertex?
OpenStudy (experimentx):
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