Use the mthod of substitution to solv the linear equation.
2x-y=2
9x-4y=11
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OpenStudy (anonymous):
2x-y=2......1
9x-4y=1.....2
from(1);
2x-2=y
using the value of y in eq(2)
9x-4(2x-2)=1
9x-8x+4=1
x+3=0
x=-3........3
using value of xin eq(1)
y=2(-3)-2
y=-6-2
y=-8
OpenStudy (anonymous):
ok i am going to see how u did this
OpenStudy (anonymous):
ok so could we do another probelm togther and i try to solve and u correct me?
OpenStudy (anonymous):
hello
OpenStudy (anonymous):
ok.....
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OpenStudy (anonymous):
but i might need your help to start it off
OpenStudy (anonymous):
same method for linear equation 6a=5-b
6a=three-b
OpenStudy (anonymous):
my number three key is out...
OpenStudy (anonymous):
6a=5-b.......1
6a=3-b........2
from(1)
5-6a=b
using it in two
6a=3-5+6a
this question had no answer......
OpenStudy (anonymous):
i think i hav to set it up this way 5-6a=b
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OpenStudy (anonymous):
my computer had frozee sorry for rplying late
OpenStudy (anonymous):
yeah...i have done it for you....
OpenStudy (anonymous):
no problem...
OpenStudy (anonymous):
ok so this problem is no solution
OpenStudy (anonymous):
wouldnt this problem be just a=6
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OpenStudy (anonymous):
yeah......bcz variables cut down..
OpenStudy (anonymous):
because 5-three=1
OpenStudy (anonymous):
divide by 6=6
OpenStudy (anonymous):
oh ok i see i am going to graph this one and no solution. Thank you
OpenStudy (anonymous):
welcome....
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OpenStudy (anonymous):
in which class you are???
OpenStudy (anonymous):
algebra
OpenStudy (anonymous):
intermediate
OpenStudy (anonymous):
what about u
OpenStudy (anonymous):
i am in university.......software engineering
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OpenStudy (anonymous):
oh ok well im in healthscience
OpenStudy (anonymous):
well i am having a probelm with this particular homework assignment
OpenStudy (anonymous):
i dont remeber how to solve some of these problems