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Mathematics 20 Online
OpenStudy (anonymous):

Factor completely 10ax^2-23ax-5a

OpenStudy (anonymous):

a(5x+1)(2x-5)

OpenStudy (anonymous):

explain please

OpenStudy (anonymous):

It's 10ax squared

OpenStudy (anonymous):

you would first factor out a because its a common factor between all three terms and you get a(10x^2-23x-5)

OpenStudy (anonymous):

is that all

OpenStudy (anonymous):

then u would use completing the square you replace -23 x with 2x-25x and you get a(10x^2+2x-25x-5) factor by grouping so you get a(2x(5x+1)) - 5(5x+1)) and since 5x+1 is a common factor you get a(5x+1)(2x-5)

OpenStudy (anonymous):

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