Question

integral 0 to 1 dx/x^2
the dx/x^2 is a fraction and i dont know where to start

Answer 1

Say that 1/x^2 is x^(-2)

Answer 2

but wut i am suppose to do w/ the x^-2 after that? that is wut i am confused on

Answer 3

\[\int x^ndx=\frac{x^{n+1}}{n+1}+C\]

Answer 4

answer is (x^(-2+1))/(-2+1)=-1/x

Answer 5

thatz all there is to it?

Answer 6

yes