Question

2 = (√3b-2) - (√10-b)
the answer is 6... HOW?!
step by step please thanks!

Answer 1

\[2=\sqrt{3b-2} - \sqrt{10-b}\]

Answer 2

so this what i came up with? I'm not sure if I did it correctly
(2)^2 = (√3b-2)^2 - √10-b
(4)= 3b-2 (-√10-b)
(4)^2= 3b-2 (-√10-b)^2
16=3b-2 +10-b
16 = 2b+8
12= 2b
b= 6

???????