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find dy/dx of 2sinxcosy=1
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use implicit differentiation.
if you know what to do...then why can't you do it?
i want to check my answer
what's your answer?
The problem must be with the implicit deferentiation itself, the exercise demands you do it that way. So you donot want an explanation?
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i got 2cotxcoty
I think there is no 2 there
did you use product rule?
yep
because if you did...you should get this http://www.wolframalpha.com/input/?i=+dy%2Fdx+of+2sinxcosy%3D1
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but the 2 is wrong
Well are you remembering of using the chain rule when derivating the part that contains y?
ok so i got cotxcoty
then you got it already
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