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Mathematics 8 Online
OpenStudy (anonymous):

Lim x-> 0 of ((x^2* sin (1/x)). Show that it equals 0.

OpenStudy (anonymous):

\[\lim_{x \rightarrow 0} x^2 \sin \frac{ 1 }{ x }\]

OpenStudy (anonymous):

l'Hospital rule to be applied here, hint , write the x^2 in numerator as 1/1/x^2

OpenStudy (anonymous):

I think squeeze theorem can be used

OpenStudy (anonymous):

How did you go from x^2 to 1/1/x^2 ? Sorry please explain.

OpenStudy (anonymous):

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