A does a work in 36 days,B does it in 24 days and C does it in 96 days.They started doing work together,but A left the work after 9 days ,B left it before 9 days of its compeletion,how long A,B and C work together to complete the work.

Question

anonymous · Answer

work by A in one day = 1/36
work by B in one day = 1/24
work by C in one day = 1/96

ganeshie8 · Answer

9 days

anonymous · Answer

in first 9 days A,B,C work together
total work in 9 days = 9\16

anonymous · Answer

as on last nine days C has to do the work alone
therefore
work on last 9 days = 9/96

ganeshie8 · Answer

$\frac{9}{16} + (\frac{1}{24} + \frac{1}{96})d + \frac{9}{96} = 1$

anonymous · Answer

work remaining is
1 - 9/16 - 9/96
now this work can be done only B and C

ganeshie8 · Answer

total days it took for them to finish the work = 9 + d + 9