Question

Divide.
x^2-4/x-8/x-2

Answer 1

\[\frac{\frac{x^2-4}{x-8}}{x-2}\]?

Answer 2

yes.

Answer 3

same as
\[\frac{x^2-4}{(x-8)(x-2)}\] factor the numerator, and cancel the common factor of \(x-2\) top and bottom

Answer 4

as in
\[\frac{(x+2)(x-2)}{(x-8)(x-2)}\] then cancel

Answer 5

so x+2/x-8?

Answer 6

yes

Answer 7

ok ty satellite73