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Mathematics 12 Online
OpenStudy (anonymous):

i need help with log value function!

OpenStudy (anonymous):

\[\log6\sqrt[3]{6}\]

OpenStudy (anonymous):

is it log (6squareroot6)

OpenStudy (anonymous):

what is its base??

OpenStudy (anonymous):

the base is 6

OpenStudy (anonymous):

now 6[6^(1/2)] = 6^(1+1/2) =6^(3/2) log6^(3/2) to the base 6 is 3/2

OpenStudy (anonymous):

got it???

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