Question

The sum of 3 consecutive integral numbers is 117. Find the numbers.

Answer 1

x + (x+1) + (x+2) = 117

Answer 2

let smallest integer be x
so 2 integers are x,x+1,x+2
sum = 117
can u form an equation now ?

Answer 3

x is the first number in the sequence

Answer 4

oh heck guess and check!

Answer 5

jeez not equations
lets try 40
40+41+42=123 no too big try again

Answer 6

guess,by dividing by 3

Answer 7

don't forget you are a thinking person, not an equation solving machine

Answer 8

But thinking gives equation right

Answer 9

is rcb getting any of this ? :P

Answer 10

38+39+40=117

Answer 11

And YES DIVIDING BY THREE GIVES MIDDLE VALUE.

Answer 12

thought so

Answer 13

Because, (x-1)+x+(x+1)=117 { where x is the middle value}
3x=117