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Mathematics 12 Online
OpenStudy (anonymous):

Is this right?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

OpenStudy (unklerhaukus):

how did you get that/

OpenStudy (anonymous):

I did 0.34 x 0.45

OpenStudy (unklerhaukus):

since E and F are mutually exclusive \[P(E \text{ or } F)=P(E)+P(F)\]

OpenStudy (anonymous):

so it be 0.79?

hartnn (hartnn):

|dw:1349799538811:dw|

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