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Please solve this equation step by step 1/2lg(3x+1)-1=lg(x-3)-lg(5)
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is lg(3x+1) in denominator or in numerator? could you retype the question
in numerator
did you try? i can give you a hint use LogA-Log B= Log (a/b)
\[\log_{10} (3x+1)=2* [ \log_{10}[(x-3)/5]\]
3x+1= [x-3]^2 / 5^2
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25*3x+25=x^2-6x+9
now solve for x
thanks ;)
75x+25=x^2-6x+9
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