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Simplify the rational expression. State any excluded values. x^2-36/42x-7x^2=(x-6)(x+6)/7x(6-x)
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\[\frac{ x^2-36}{ 42x-7x^2 }=\frac{ (x-6)(x+6) }{ 7x(6-x)}\]
\[\frac{(x-6)(x+6)}{7x(6-x)}=\frac{(x-6)(x+6)}{-7x(x-6)}\] now, can you see it?
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