Question

Find the discriminant & describe the type of roots 6x^2-2x-4=0
Show Work!

Answer 1

@Kashan

Answer 2

Disc= b^2 - 4ac
= (-2)^2 - 4(6)(-4)
= 4+64
= 68
Disc>0 so
real and distinct roots

Answer 3

@annawilliams40285 got it..??

Answer 4

I think it is 96 not 68. But still the nature of roots is correct.. :)

Answer 5

O sorry.. mistake in calculation.. but result is correct... :)

Answer 6

@ kashan Can you show me the correct steps to get 96

Answer 7

Disc= b^2 - 4ac
= (-2)^2 - 4(6)(-4)
= 4+96
= 100
Disc>0

Answer 8

@annawilliams40285 got it now..??