Question

If the tangent line to y=f(x) at (4,3) passes through the point (0,2) find f(4) and f'(4).

Answer 1

x^2 - 15x + 56

(x-7)(x-8)= 0

x -7 = 0 or x - 8 = 0

x = -7 or -8

Answer 2

f(4) is already given. f'(4) is simply the slope between (4,3) and (0,2)