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Mathematics 10 Online
OpenStudy (anonymous):

The distance a spring stretches varies directly as the amount of weight that is hanging on it. A weight of 2.5 pounds stretches a spring 18 inches. Find the stretch of the spring when a weight of 6.4 pounds is hanging on it.

OpenStudy (lgbasallote):

varies directly means you use the equation y = kx agree?

OpenStudy (anonymous):

Yes

OpenStudy (lgbasallote):

good. so let's let y be the distance and x be the weight when weight is 2.5 punds, distance is 18 inches.. so 18 = k(2.5) can you solve for k?

OpenStudy (anonymous):

k=7.2

OpenStudy (lgbasallote):

right. so k is 7.2 now the question is..what is the distance when weight is 6.4 pounds so the equation is just y = (7.2)(6.4) solve for y

OpenStudy (anonymous):

46.08

OpenStudy (lgbasallote):

right

OpenStudy (anonymous):

Thank You!

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