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The distance a spring stretches varies directly as the amount of weight that is hanging on it. A weight of 2.5 pounds stretches a spring 18 inches. Find the stretch of the spring when a weight of 6.4 pounds is hanging on it.
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varies directly means you use the equation y = kx agree?
Yes
good. so let's let y be the distance and x be the weight when weight is 2.5 punds, distance is 18 inches.. so 18 = k(2.5) can you solve for k?
k=7.2
right. so k is 7.2 now the question is..what is the distance when weight is 6.4 pounds so the equation is just y = (7.2)(6.4) solve for y
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46.08
right
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