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a chain is held on a frictionless table with 1/3 of its length hanging over the edge. If the chain has length L = 25 cm and mass m = 34 g, how much work is required to pull the hanging part back onto the table?
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\[\huge \int\limits_{0}^{\frac{.25 }{ 3}}\frac{ .034 }{ .25}*g*y dy\]
the answer suppose to be in Newtons
it is.
see the meters and kg in that equation?
No, if the answer is the work needed, the answer must be in joules, not in newtons.
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I think he meant newton meters. but whatever.
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