a chain is held on a frictionless table with 1/3 of its length hanging over the edge. If the chain has length L = 25 cm and mass m = 34 g, how much work is required to pull the hanging part back onto the table?

Question

anonymous · Answer

$$\huge \int\limits_{0}^{\frac{.25 }{ 3}}\frac{ .034 }{ .25}*g*y dy$$

anonymous · Answer

the answer suppose to be in Newtons

anonymous · Answer

it is.

anonymous · Answer

see the meters and kg in that equation?

vincent-lyon.fr · Answer

No, if the answer is the work needed, the answer must be in joules, not in  newtons.

anonymous · Answer

I think he meant newton meters.  but whatever.