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Mathematics 6 Online
OpenStudy (anonymous):

y = (x^2 + 1)(sechx (ln x))

OpenStudy (anonymous):

I need the derivatives pls help

OpenStudy (anonymous):

product and chain rules derivative of sechx is -sechxtanhx if you know your derivative rules, should be pretty easy from here

OpenStudy (anonymous):

The answer is 4, i can't get that

OpenStudy (anonymous):

\[y'=(x^2+1)(-sechxtanhx(lnx))(\frac{1}{x})+sechx(lnx)(2x)\]

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