Question

express (1-i)(2+3i) / (4+2i) in form a+ib ??

Answer 1

Try to foil the numerato first. Once you do that, then you need to rationalize the denominator (multiply by its complement[which means multiply by 4-2i to get 4*4 + 8i - 8i -4i^2 which is a constant since all the i's go away])

Answer 2

Just to be clear, you need to multiply top and bottom by the complement (conjugate)....