what is standard form? and how do I sovle through: (-4,3), parallel to y=-5/4x-3
parallel lines have same slope so what is the slope of the required line ?
so they have the same slope?
then to perpendicular have recpical slope?
negative reciprocal to be precise. -1/(slope)
okay but how do I solve through: (-4,3), parallel to y=-5/4x-3
in standard form
whats the slope of line y=-5/4x-3 ? u know how to find ?
-5/4
thats correct! so , since parallel lines have same slope , u got the slope of your line as -5/4 now, put that in any of the line equation form you know , then convert it into standard form
standard form is ax+by+c=0
so it would be like -4x+3y+-5/4=0
Im lost
which form of line u know ? u know y=mx+b ?
yes
but i need to have it in standard form
in it y=-5/4x-2
m=slope = -5/4 now put the point in that to find b. we'll convert it to standard form after u find b
in b=-2
or -5
yes, thats correct. y=-5/4x-2 now we need to bring that in form of ax+by+c=0 multiply 4 on both sides to eliminate fraction
no wait i mean it's b=-8
b= -2 was correct. 3= -5/4(-4)+b gives b=-2
oh okay
y=-5/4x-2 now we need to bring that in form of ax+by+c=0 multiply 4 on both sides to eliminate fraction
oh so it would be 4y=-5x-2
-2*4 = -8
oh so do I always have to multipy it to the b
4 was to be multiplied to every term , both sides.
oh okay then what is the next step
u get 4y= -5x-8, right ? add 5x+8 to both sides to get 0 on right side
yes
then what do I do what do u mean add it
4y+5x+8 = -5x-8+5x+8 = 0 so u get 5x+4y + 8= 0 <---standard form
but I thought the answer was 5x+4y=-8
yes! thats is standard form . ax+by =c so you are correct.
oh okay thank you so much and sorry for the hard time
no problem. welcome ^_^
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