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Mathematics 10 Online
OpenStudy (anonymous):

What is the derivative of 2x/(x^2 + cosy) with respect to x?

OpenStudy (anonymous):

Do you know the quotient rule?

OpenStudy (anonymous):

g'(x)h(x) - g(x)h'(x)/[h(x)]^2 ?

OpenStudy (anonymous):

Yep! Because you are taking the derivative with respect to x, cos(y)=0

OpenStudy (anonymous):

So it ends up being ((x^2 + cosy)(2) - (2x)(2x))/(x^2 + cosy)^2 ?

OpenStudy (anonymous):

Yep

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