Question

Find an equation of the line tangent to the curve 2y^2-x^2=1 at the point (7, -5)

Answer 1

Can you find dy/dx?

Answer 2

\[y' = x/2y\]

Answer 3

Correct :) Now plug the coordinate ( 7, -5) to get slope .

Answer 4

Tangent line equation:
y = m ( x - 7) -5

Answer 5

Do you want to post your result up?

Answer 6

I get y= -7x/10 - 1/10, but it's wrong according to the answer key.

Answer 7

I double check, there's nothing wrong with it. You can talk to your teacher.

Answer 8

Thanks!