Question

The length of a rectangle is 2ft longer than its width.
If the perimeter of the rectangle is 40ft , find its area.

Answer 1

\[2w + 2(w+2) = 40\]

Answer 2

2w+2w+4=40?

Answer 3

this should help you compute w and l

Answer 4

\[l(length)= w+2\]

Answer 5

i dont get it

Answer 6

\[A _{rectangle}= l * w\]
\[w=width,l=length\]
\[length=width + 2ft\]
\[width + width +(width+2) +(width+2) = 40ft\]

Answer 7

solve for w and you will get the value of the width. add 2 ft and you will get the value of the length. compute area using these values.