Question

Discrete Mathematics question:

How to write a step-by-step algorithm for raising a certain number to a certain exponent?

Answer 1

how do you think it please ?

Answer 2

...for example ?

Answer 3

def exponent(number, power)
return number**power

There you are, algorithm:-)

Answer 4

that seems a bit short @estudier isn't it? i mean the algorithm loops doesn't it?

Answer 5

It's a function, you call it, like

exponent(3,6) and it returns 3^6

I am not really sure what you are looking for to be honest.

Any program code can be rewritten as an algorithm.

Answer 6

would a javascript code help? lol

Answer 7

really?

Answer 8

and i prefer c @gaara438125

Answer 9

but an algorithm has to be detailed enough for a program to run right @estudier ?

Answer 10

i prefer C++ lol

Answer 11

@lgbasallote

A function is a built in type in many programming languages ( bit like math, really)

Most higher level programming languages are abstract or "high-level".

I mean, in theory, you could write the algorithm in machine language but it would be very long and completely incomprehensible.

Answer 12

hmm fair enough

Answer 13

I can execute that code on my computer just as it is but it does rely on the language framework having already been set up on my computer.

Answer 14

i just couldn't figure out how to initiate my loop....

Answer 15

i thought discrete math algorithm could help....

Answer 16

Oh, I see, your are dropping a level of abstraction....

Answer 17

You want to do it as repeated multiplication or something like that?

Answer 18

yes...something like that

Answer 19

Here is one I just lifted off the web

int powerFunc(int x, int y)
{
for (int i = 0; i < x; i++)
{
sum *= y; // here it will keep mulitplying itself until
// the condition is met
}

return (sum);
}

your main would look like this:

int result = powerFun(x,y);

Answer 20

This is still relying on a function call to work but has a loop structure...

Answer 21

no idea what that means////

Answer 22

ie the bit about multiplying until a condition is met.....

Answer 23

nevermind the question....i'll just try to think about it

Answer 24

K.