(4x - 3)2 = 121
need help with this problem (4x - 3)2 = 121 thanks
8x-6= 121 8x=127 x=127/8 x=15.875 like this maybe?
\[(4x-3)^{2}\]
or is it that?
take square root of both sides: 4x - 3 = 11 or 4x -3 = -11
i've assumed its (4x - 3)^2
if its times 2 then donclux has got it
ill write the other one too :) in a sec
@cwrw238 yes this is correct (4x-3)^2=121
@donciux123 , looks correct but what are the steps that you use to work out the problem this way i know.
\[(4x-3)^{2} =121\] \[16x ^{2} -24x + 9 = 121\] \[16x ^{2} -24x +130\] \[D=(-24)^{2}- 4*16*130=576 -8320= -7744\] and its imposibruu
so is it the first one or the second one?
@donciux123 it is the first one
so its like this \[4x*2 - 3*2 = 121\] \[8x -6 =121\] \[8x= 121 +6\] \[8x=127\] \[x=127/8\] \[x = 15,875\]
(4x-3)^2 = 121 never seen it written the way you did it
so it is the second one.... i wrote that already... but i couldnt solve it ... couse i cant use D :D
alternatively 4x - 3 = 11 4x = 14 x = 3.5 or 4x-3 = -11 4x = -8 x = -2
Ohh.. forgot about that way :DD |dw:1349961329760:dw|
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