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y=10000*0.8^x if y is dollas and x is year. please help
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\[y = 10000 * .8^x\]
yes. I could not solve that question
what are you trying to solve?
i could fine in percent/year
if y is money and x is year so hur big is cost in percent per year
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@across
I am so confused. What are you trying to do? Solve for \(x\)?
yes
Do you know how to work with logarithms?
\[ y=10000\cdot0.8^x\\ \log_{0.8}y=\log_{0.8}10000+\log_{0.8}0.8^x\\ \log_{0.8}y=\log_{0.8}10000+x\\ x=\log_{0.8}y-\log_{0.8}10000\\ x=\log_{0.8}\frac{y}{10000} \]
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i do not know that. thats why i could not do that question also its not in the book :((
how to get the percent/year because i could not know the result of y
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