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solve the following: x=6+3z y+2z=2 7x-5z=3y+14
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once you substitute x and y into 7x - 5z = 3y + 14 you get 42 + 21z = 6 -6z + 14
that's it?
well, no, you're solving for X, Y, and Z right?
yes
help me to finish it please
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i just realize i left out a -5z so messed everything up lol.
Z = 1 can you find the rest or you still need help?
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