Question

HELP PEOPLE HARD MATH QUESTION :0

Answer 1

Simplify the expression

\[\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\]


If the simplified expression is written in standard form, what is the leading coefficient?

Answer 2

Hint:\[3^3=27\]

Answer 3

so the answer is 3 lol?

Answer 4

but it's a sqrt not a cubed root?

Answer 5

huh?

Answer 6

across stated that 3cubed is 27 i'm waiting for her to reply to help us understand why o.o

Answer 7

oh yea ^^

Answer 8

the only coefficient i see is 2

Answer 9

across is taking forever to answer lol

Answer 10

wait did we get the answer?

Answer 11

you just deleted that whole thing?!

Answer 12

i made an error

Answer 13

what ^^

Answer 14

\[\quad\sqrt{27x ^{5}} + x \sqrt{3} + 9\sqrt{3x}\]\[=\sqrt{3^3}x ^{5/2} + \sqrt{3}x^1 + 9\sqrt{3}x^{1/2}\]\[=3\sqrt{3}x^2x ^{1/2} + \sqrt{3}x^{1/2}x^{1/2} + 9\sqrt{3}x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt 3x^{1/2}\]\[=(x^2 + x^{1/2} + 9)\sqrt {3x}\]

Answer 15

so thats the answer LOL

Answer 16

hmm

Answer 17

the last part is right?

Answer 18

maybe my second line in more useful

Answer 19

what do u mean?