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if a and b are the roots of the equation 2x²-6x-8=0 , find the value of : a^2 - b^2 .
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is that suppose to be 2x²-6x-8=0
yes, typo :)
A²-B²= -5 ?? @amorfide
A²-B²= -17 ?
oops wait i got mixed up ignore that i will do your solution now A and b are roots of this equation 2x²-6x-8=0 A+B=-b/a A+B=6/2 A+B=3 AB=c/a AB=-8/2 AB=-4 A²-B²=(A-B)(A+B) (A-B)²=(A+B)²-4AB=3²-4(-4)=9+16=25 so A-B=square root of 25 A-B= plus or minus 5 A²-B²=(A+B)(A-B)=3(5) or A²-B²=(A+B)(A-B)=3(-5) A-b= 15 or -15
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the final asnwer for a = 15 and b = -15 @amorfide
A²-B²=15 or -15
thank you so much @amorfide question solved :)
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