Question

xy^2+4xy=10

find dy/dx

Answer 1

x*2yy'+y^2 + 4xy' + 4y = 0
x*2yy'+4xy' = -(4y+y^2)
y'(2xy+4x)=-(4y+y^2)

Answer 2

y'=dy/dx = -y(4+y)/[2x(y+2)]

Answer 3

check the arithmetic

Answer 4

I'm a little confused what are the * for?

Answer 5

darn it im too slow :(\[\frac{d}{dx} \left(xy^{2}\right) +\frac{d}{dx} \left(4xy\right) =\frac{d}{dx} \left(10\right) => x2yy' +y^2 + 4xy'+y =0\]

Answer 6

you use the product rule

Answer 7

* means times

Answer 8

I'm wretched at caluculus. Thank you so much