Question

Find Derivative
g(x) = cosh(ln x)

Answer 1

Do know the derivatives of hyperbolic functions?

Answer 2

\[cosh(x)=\frac{e^x+e^{-x}}{2}=\frac{e^x}{2}+\frac{e^{-x}}{2}\]

\[sinh(x)=\frac{e^x-e^{-x}}{2}=\frac{e^x}{2}-\frac{e^{-x}}{2}\]

That might make the derivative easier

Answer 3

g(x)=(x^2+1)/(2x)