Question

(x-1)y'+2xy=0 , y(2) = a : Solution?

Answer 1

change it into :
y'/y = -2x / (x-1)

now integrate :

-2x/(x-1) = -2 - 2/(x-1)

so :
ln|y| = -2x -2ln|x-1| + c

y = C * e^(-2x -2ln|x-1|)

can you do it now ?