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Modern Algebra: Is S={a,b|a+b=0} a subring of Z x Z? Justify.
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I think it's false but I don't know why :(
is (-1,1) in S?
Someone told me it was closed under multiplication which is what I'm having trouble understanding.
Also (-1,1) is in Z.
what is (-1,1)*(-1,1)
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(-1,1) is in \(Z\times Z\)
what is (-1,1)*(-1,1)
(1,1)
is (1,1) in S?
I guess 1 is not equal to 0 so no?
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correct....you have your answer ;)
Oh, well thank you!
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